Optimal. Leaf size=336 \[ -\frac {d (d x)^{5/2}}{6 b \left (a+b x^2\right )^3}-\frac {5 d^3 \sqrt {d x}}{48 b^2 \left (a+b x^2\right )^2}+\frac {5 d^3 \sqrt {d x}}{192 a b^2 \left (a+b x^2\right )}-\frac {5 d^{7/2} \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{128 \sqrt {2} a^{7/4} b^{9/4}}+\frac {5 d^{7/2} \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{128 \sqrt {2} a^{7/4} b^{9/4}}-\frac {5 d^{7/2} \log \left (\sqrt {a} \sqrt {d}+\sqrt {b} \sqrt {d} x-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d x}\right )}{256 \sqrt {2} a^{7/4} b^{9/4}}+\frac {5 d^{7/2} \log \left (\sqrt {a} \sqrt {d}+\sqrt {b} \sqrt {d} x+\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d x}\right )}{256 \sqrt {2} a^{7/4} b^{9/4}} \]
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Rubi [A]
time = 0.23, antiderivative size = 336, normalized size of antiderivative = 1.00, number of steps
used = 14, number of rules used = 10, integrand size = 28, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.357, Rules used = {28, 294, 296,
335, 217, 1179, 642, 1176, 631, 210} \begin {gather*} -\frac {5 d^{7/2} \text {ArcTan}\left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{128 \sqrt {2} a^{7/4} b^{9/4}}+\frac {5 d^{7/2} \text {ArcTan}\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}+1\right )}{128 \sqrt {2} a^{7/4} b^{9/4}}-\frac {5 d^{7/2} \log \left (-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d x}+\sqrt {a} \sqrt {d}+\sqrt {b} \sqrt {d} x\right )}{256 \sqrt {2} a^{7/4} b^{9/4}}+\frac {5 d^{7/2} \log \left (\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d x}+\sqrt {a} \sqrt {d}+\sqrt {b} \sqrt {d} x\right )}{256 \sqrt {2} a^{7/4} b^{9/4}}+\frac {5 d^3 \sqrt {d x}}{192 a b^2 \left (a+b x^2\right )}-\frac {5 d^3 \sqrt {d x}}{48 b^2 \left (a+b x^2\right )^2}-\frac {d (d x)^{5/2}}{6 b \left (a+b x^2\right )^3} \end {gather*}
Antiderivative was successfully verified.
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Rule 28
Rule 210
Rule 217
Rule 294
Rule 296
Rule 335
Rule 631
Rule 642
Rule 1176
Rule 1179
Rubi steps
\begin {align*} \int \frac {(d x)^{7/2}}{\left (a^2+2 a b x^2+b^2 x^4\right )^2} \, dx &=b^4 \int \frac {(d x)^{7/2}}{\left (a b+b^2 x^2\right )^4} \, dx\\ &=-\frac {d (d x)^{5/2}}{6 b \left (a+b x^2\right )^3}+\frac {1}{12} \left (5 b^2 d^2\right ) \int \frac {(d x)^{3/2}}{\left (a b+b^2 x^2\right )^3} \, dx\\ &=-\frac {d (d x)^{5/2}}{6 b \left (a+b x^2\right )^3}-\frac {5 d^3 \sqrt {d x}}{48 b^2 \left (a+b x^2\right )^2}+\frac {1}{96} \left (5 d^4\right ) \int \frac {1}{\sqrt {d x} \left (a b+b^2 x^2\right )^2} \, dx\\ &=-\frac {d (d x)^{5/2}}{6 b \left (a+b x^2\right )^3}-\frac {5 d^3 \sqrt {d x}}{48 b^2 \left (a+b x^2\right )^2}+\frac {5 d^3 \sqrt {d x}}{192 a b^2 \left (a+b x^2\right )}+\frac {\left (5 d^4\right ) \int \frac {1}{\sqrt {d x} \left (a b+b^2 x^2\right )} \, dx}{128 a b}\\ &=-\frac {d (d x)^{5/2}}{6 b \left (a+b x^2\right )^3}-\frac {5 d^3 \sqrt {d x}}{48 b^2 \left (a+b x^2\right )^2}+\frac {5 d^3 \sqrt {d x}}{192 a b^2 \left (a+b x^2\right )}+\frac {\left (5 d^3\right ) \text {Subst}\left (\int \frac {1}{a b+\frac {b^2 x^4}{d^2}} \, dx,x,\sqrt {d x}\right )}{64 a b}\\ &=-\frac {d (d x)^{5/2}}{6 b \left (a+b x^2\right )^3}-\frac {5 d^3 \sqrt {d x}}{48 b^2 \left (a+b x^2\right )^2}+\frac {5 d^3 \sqrt {d x}}{192 a b^2 \left (a+b x^2\right )}+\frac {\left (5 d^2\right ) \text {Subst}\left (\int \frac {\sqrt {a} d-\sqrt {b} x^2}{a b+\frac {b^2 x^4}{d^2}} \, dx,x,\sqrt {d x}\right )}{128 a^{3/2} b}+\frac {\left (5 d^2\right ) \text {Subst}\left (\int \frac {\sqrt {a} d+\sqrt {b} x^2}{a b+\frac {b^2 x^4}{d^2}} \, dx,x,\sqrt {d x}\right )}{128 a^{3/2} b}\\ &=-\frac {d (d x)^{5/2}}{6 b \left (a+b x^2\right )^3}-\frac {5 d^3 \sqrt {d x}}{48 b^2 \left (a+b x^2\right )^2}+\frac {5 d^3 \sqrt {d x}}{192 a b^2 \left (a+b x^2\right )}-\frac {\left (5 d^{7/2}\right ) \text {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d}}{\sqrt [4]{b}}+2 x}{-\frac {\sqrt {a} d}{\sqrt {b}}-\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d} x}{\sqrt [4]{b}}-x^2} \, dx,x,\sqrt {d x}\right )}{256 \sqrt {2} a^{7/4} b^{9/4}}-\frac {\left (5 d^{7/2}\right ) \text {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d}}{\sqrt [4]{b}}-2 x}{-\frac {\sqrt {a} d}{\sqrt {b}}+\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d} x}{\sqrt [4]{b}}-x^2} \, dx,x,\sqrt {d x}\right )}{256 \sqrt {2} a^{7/4} b^{9/4}}+\frac {\left (5 d^4\right ) \text {Subst}\left (\int \frac {1}{\frac {\sqrt {a} d}{\sqrt {b}}-\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d} x}{\sqrt [4]{b}}+x^2} \, dx,x,\sqrt {d x}\right )}{256 a^{3/2} b^{5/2}}+\frac {\left (5 d^4\right ) \text {Subst}\left (\int \frac {1}{\frac {\sqrt {a} d}{\sqrt {b}}+\frac {\sqrt {2} \sqrt [4]{a} \sqrt {d} x}{\sqrt [4]{b}}+x^2} \, dx,x,\sqrt {d x}\right )}{256 a^{3/2} b^{5/2}}\\ &=-\frac {d (d x)^{5/2}}{6 b \left (a+b x^2\right )^3}-\frac {5 d^3 \sqrt {d x}}{48 b^2 \left (a+b x^2\right )^2}+\frac {5 d^3 \sqrt {d x}}{192 a b^2 \left (a+b x^2\right )}-\frac {5 d^{7/2} \log \left (\sqrt {a} \sqrt {d}+\sqrt {b} \sqrt {d} x-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d x}\right )}{256 \sqrt {2} a^{7/4} b^{9/4}}+\frac {5 d^{7/2} \log \left (\sqrt {a} \sqrt {d}+\sqrt {b} \sqrt {d} x+\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d x}\right )}{256 \sqrt {2} a^{7/4} b^{9/4}}+\frac {\left (5 d^{7/2}\right ) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{128 \sqrt {2} a^{7/4} b^{9/4}}-\frac {\left (5 d^{7/2}\right ) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{128 \sqrt {2} a^{7/4} b^{9/4}}\\ &=-\frac {d (d x)^{5/2}}{6 b \left (a+b x^2\right )^3}-\frac {5 d^3 \sqrt {d x}}{48 b^2 \left (a+b x^2\right )^2}+\frac {5 d^3 \sqrt {d x}}{192 a b^2 \left (a+b x^2\right )}-\frac {5 d^{7/2} \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{128 \sqrt {2} a^{7/4} b^{9/4}}+\frac {5 d^{7/2} \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {d x}}{\sqrt [4]{a} \sqrt {d}}\right )}{128 \sqrt {2} a^{7/4} b^{9/4}}-\frac {5 d^{7/2} \log \left (\sqrt {a} \sqrt {d}+\sqrt {b} \sqrt {d} x-\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d x}\right )}{256 \sqrt {2} a^{7/4} b^{9/4}}+\frac {5 d^{7/2} \log \left (\sqrt {a} \sqrt {d}+\sqrt {b} \sqrt {d} x+\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {d x}\right )}{256 \sqrt {2} a^{7/4} b^{9/4}}\\ \end {align*}
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Mathematica [A]
time = 0.43, size = 164, normalized size = 0.49 \begin {gather*} \frac {d^3 \sqrt {d x} \left (\frac {4 a^{3/4} \sqrt [4]{b} \sqrt {x} \left (-15 a^2-42 a b x^2+5 b^2 x^4\right )}{\left (a+b x^2\right )^3}-15 \sqrt {2} \tan ^{-1}\left (\frac {\sqrt {a}-\sqrt {b} x}{\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}}\right )+15 \sqrt {2} \tanh ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{a} \sqrt [4]{b} \sqrt {x}}{\sqrt {a}+\sqrt {b} x}\right )\right )}{768 a^{7/4} b^{9/4} \sqrt {x}} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.06, size = 206, normalized size = 0.61
method | result | size |
derivativedivides | \(2 d^{7} \left (\frac {\frac {5 \left (d x \right )^{\frac {9}{2}}}{384 a \,d^{2}}-\frac {7 \left (d x \right )^{\frac {5}{2}}}{64 b}-\frac {5 a \,d^{2} \sqrt {d x}}{128 b^{2}}}{\left (d^{2} x^{2} b +a \,d^{2}\right )^{3}}+\frac {5 \left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {d x +\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {a \,d^{2}}{b}}}{d x -\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {a \,d^{2}}{b}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}+1\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}-1\right )\right )}{1024 a^{2} d^{4} b^{2}}\right )\) | \(206\) |
default | \(2 d^{7} \left (\frac {\frac {5 \left (d x \right )^{\frac {9}{2}}}{384 a \,d^{2}}-\frac {7 \left (d x \right )^{\frac {5}{2}}}{64 b}-\frac {5 a \,d^{2} \sqrt {d x}}{128 b^{2}}}{\left (d^{2} x^{2} b +a \,d^{2}\right )^{3}}+\frac {5 \left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {d x +\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {a \,d^{2}}{b}}}{d x -\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {a \,d^{2}}{b}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}+1\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {a \,d^{2}}{b}\right )^{\frac {1}{4}}}-1\right )\right )}{1024 a^{2} d^{4} b^{2}}\right )\) | \(206\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.50, size = 332, normalized size = 0.99 \begin {gather*} \frac {\frac {8 \, {\left (5 \, \left (d x\right )^{\frac {9}{2}} b^{2} d^{6} - 42 \, \left (d x\right )^{\frac {5}{2}} a b d^{8} - 15 \, \sqrt {d x} a^{2} d^{10}\right )}}{a b^{5} d^{6} x^{6} + 3 \, a^{2} b^{4} d^{6} x^{4} + 3 \, a^{3} b^{3} d^{6} x^{2} + a^{4} b^{2} d^{6}} + \frac {15 \, {\left (\frac {\sqrt {2} d^{6} \log \left (\sqrt {b} d x + \sqrt {2} \left (a d^{2}\right )^{\frac {1}{4}} \sqrt {d x} b^{\frac {1}{4}} + \sqrt {a} d\right )}{\left (a d^{2}\right )^{\frac {3}{4}} b^{\frac {1}{4}}} - \frac {\sqrt {2} d^{6} \log \left (\sqrt {b} d x - \sqrt {2} \left (a d^{2}\right )^{\frac {1}{4}} \sqrt {d x} b^{\frac {1}{4}} + \sqrt {a} d\right )}{\left (a d^{2}\right )^{\frac {3}{4}} b^{\frac {1}{4}}} + \frac {2 \, \sqrt {2} d^{5} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \left (a d^{2}\right )^{\frac {1}{4}} b^{\frac {1}{4}} + 2 \, \sqrt {d x} \sqrt {b}\right )}}{2 \, \sqrt {\sqrt {a} \sqrt {b} d}}\right )}{\sqrt {\sqrt {a} \sqrt {b} d} \sqrt {a}} + \frac {2 \, \sqrt {2} d^{5} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \left (a d^{2}\right )^{\frac {1}{4}} b^{\frac {1}{4}} - 2 \, \sqrt {d x} \sqrt {b}\right )}}{2 \, \sqrt {\sqrt {a} \sqrt {b} d}}\right )}{\sqrt {\sqrt {a} \sqrt {b} d} \sqrt {a}}\right )}}{a b^{2}}}{1536 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.35, size = 389, normalized size = 1.16 \begin {gather*} \frac {60 \, {\left (a b^{5} x^{6} + 3 \, a^{2} b^{4} x^{4} + 3 \, a^{3} b^{3} x^{2} + a^{4} b^{2}\right )} \left (-\frac {d^{14}}{a^{7} b^{9}}\right )^{\frac {1}{4}} \arctan \left (-\frac {\sqrt {d x} a^{5} b^{7} d^{3} \left (-\frac {d^{14}}{a^{7} b^{9}}\right )^{\frac {3}{4}} - \sqrt {a^{4} b^{4} \sqrt {-\frac {d^{14}}{a^{7} b^{9}}} + d^{7} x} a^{5} b^{7} \left (-\frac {d^{14}}{a^{7} b^{9}}\right )^{\frac {3}{4}}}{d^{14}}\right ) + 15 \, {\left (a b^{5} x^{6} + 3 \, a^{2} b^{4} x^{4} + 3 \, a^{3} b^{3} x^{2} + a^{4} b^{2}\right )} \left (-\frac {d^{14}}{a^{7} b^{9}}\right )^{\frac {1}{4}} \log \left (5 \, a^{2} b^{2} \left (-\frac {d^{14}}{a^{7} b^{9}}\right )^{\frac {1}{4}} + 5 \, \sqrt {d x} d^{3}\right ) - 15 \, {\left (a b^{5} x^{6} + 3 \, a^{2} b^{4} x^{4} + 3 \, a^{3} b^{3} x^{2} + a^{4} b^{2}\right )} \left (-\frac {d^{14}}{a^{7} b^{9}}\right )^{\frac {1}{4}} \log \left (-5 \, a^{2} b^{2} \left (-\frac {d^{14}}{a^{7} b^{9}}\right )^{\frac {1}{4}} + 5 \, \sqrt {d x} d^{3}\right ) + 4 \, {\left (5 \, b^{2} d^{3} x^{4} - 42 \, a b d^{3} x^{2} - 15 \, a^{2} d^{3}\right )} \sqrt {d x}}{768 \, {\left (a b^{5} x^{6} + 3 \, a^{2} b^{4} x^{4} + 3 \, a^{3} b^{3} x^{2} + a^{4} b^{2}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (d x\right )^{\frac {7}{2}}}{\left (a + b x^{2}\right )^{4}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 3.29, size = 304, normalized size = 0.90 \begin {gather*} \frac {1}{1536} \, d^{3} {\left (\frac {30 \, \sqrt {2} \left (a b^{3} d^{2}\right )^{\frac {1}{4}} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}} + 2 \, \sqrt {d x}\right )}}{2 \, \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}}}\right )}{a^{2} b^{3}} + \frac {30 \, \sqrt {2} \left (a b^{3} d^{2}\right )^{\frac {1}{4}} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}} - 2 \, \sqrt {d x}\right )}}{2 \, \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}}}\right )}{a^{2} b^{3}} + \frac {15 \, \sqrt {2} \left (a b^{3} d^{2}\right )^{\frac {1}{4}} \log \left (d x + \sqrt {2} \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x} + \sqrt {\frac {a d^{2}}{b}}\right )}{a^{2} b^{3}} - \frac {15 \, \sqrt {2} \left (a b^{3} d^{2}\right )^{\frac {1}{4}} \log \left (d x - \sqrt {2} \left (\frac {a d^{2}}{b}\right )^{\frac {1}{4}} \sqrt {d x} + \sqrt {\frac {a d^{2}}{b}}\right )}{a^{2} b^{3}} + \frac {8 \, {\left (5 \, \sqrt {d x} b^{2} d^{6} x^{4} - 42 \, \sqrt {d x} a b d^{6} x^{2} - 15 \, \sqrt {d x} a^{2} d^{6}\right )}}{{\left (b d^{2} x^{2} + a d^{2}\right )}^{3} a b^{2}}\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 4.26, size = 150, normalized size = 0.45 \begin {gather*} \frac {5\,d^{7/2}\,\mathrm {atan}\left (\frac {b^{1/4}\,\sqrt {d\,x}}{{\left (-a\right )}^{1/4}\,\sqrt {d}}\right )}{128\,{\left (-a\right )}^{7/4}\,b^{9/4}}-\frac {\frac {7\,d^7\,{\left (d\,x\right )}^{5/2}}{32\,b}-\frac {5\,d^5\,{\left (d\,x\right )}^{9/2}}{192\,a}+\frac {5\,a\,d^9\,\sqrt {d\,x}}{64\,b^2}}{a^3\,d^6+3\,a^2\,b\,d^6\,x^2+3\,a\,b^2\,d^6\,x^4+b^3\,d^6\,x^6}+\frac {5\,d^{7/2}\,\mathrm {atanh}\left (\frac {b^{1/4}\,\sqrt {d\,x}}{{\left (-a\right )}^{1/4}\,\sqrt {d}}\right )}{128\,{\left (-a\right )}^{7/4}\,b^{9/4}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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